How to print a linebreak in a python function?

How to print a linebreak in a python function?

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I have a list of strings in my code;

A = ['a1', 'a2', 'a3' ...]
B = ['b1', 'b2', 'b3' ...]

and I want to print them separated by a linebreak, like this:

>a1
b1
>a2
b2
>a3
b3

I've tried:

print '>' + A + '/n' + B

But /n isn't recognized like a line break.

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You have your slash backwards, it should be "\n"

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The newline character is actually '\n'.

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for pair in zip(A, B):
    print ">"+'\n'.join(pair)

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>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']

>>> for x in A:
        for i in B:
            print ">" + x + "\n" + i

Outputs:

>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3

Notice that you are using /n which is not correct!

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All three way you can use for newline character :

'\n'

"\n"

"""\n"""

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\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.

---

You can print a native linebreak using the standard os library

import os
with open('test.txt','w') as f:
    f.write(os.linesep)

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Also if you're making it a console program, you can do: print(" ") and continue your program. I've found it the easiest way to separate my text.

참고URL : https://stackoverflow.com/questions/5982206/how-to-print-a-linebreak-in-a-python-function