특정 URL에 대해 스프링 보안을 비활성화하는 방법

특정 URL에 대해 스프링 보안을 비활성화하는 방법

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상태 비 저장 스프링 보안을 사용하고 있지만 가입시 스프링 보안을 비활성화하고 싶습니다.

antMatchers("/api/v1/signup").permitAll().

하지만 작동하지 않습니다. 아래 오류가 발생합니다.

 message=An Authentication object was not found in the SecurityContext, type=org.springframework.security.authentication.AuthenticationCredentialsNotFoundException

이것은 스프링 보안 필터가 작동하고 있음을 의미한다고 생각합니다.

내 URL의 순서는 항상 "/ api / v1"입니다.

내 봄 구성은

@Override
    protected void configure(HttpSecurity http) throws Exception {

         http.
         csrf().disable().
         sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS).
         and().
         authorizeRequests().
         antMatchers("/api/v1/signup").permitAll().
         anyRequest().authenticated().
         and().
         anonymous().disable();
        http.addFilterBefore(new AuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class);
    }

내 인증 필터는

@Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        HttpServletRequest httpRequest = asHttp(request);
        HttpServletResponse httpResponse = asHttp(response);

        String username = httpRequest.getHeader("X-Auth-Username");
        String password = httpRequest.getHeader("X-Auth-Password");
        String token = httpRequest.getHeader("X-Auth-Token");

        String resourcePath = new UrlPathHelper().getPathWithinApplication(httpRequest);

        try {

            if (postToAuthenticate(httpRequest, resourcePath)) {            
                processUsernamePasswordAuthentication(httpResponse, username, password);
                return;
            }

            if(token != null){
                processTokenAuthentication(token);
            }
            chain.doFilter(request, response);
        } catch (InternalAuthenticationServiceException internalAuthenticationServiceException) {
            SecurityContextHolder.clearContext();
            logger.error("Internal authentication service exception", internalAuthenticationServiceException);
            httpResponse.sendError(HttpServletResponse.SC_INTERNAL_SERVER_ERROR);
        } catch (AuthenticationException authenticationException) {
            SecurityContextHolder.clearContext();
            httpResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED, authenticationException.getMessage());
        } finally {
        }
    }

     private HttpServletRequest asHttp(ServletRequest request) {
            return (HttpServletRequest) request;
        }

        private HttpServletResponse asHttp(ServletResponse response) {
            return (HttpServletResponse) response;
        }

        private boolean postToAuthenticate(HttpServletRequest httpRequest, String resourcePath) {
            return Constant.AUTHENTICATE_URL.equalsIgnoreCase(resourcePath) && httpRequest.getMethod().equals("POST");
        }

        private void processUsernamePasswordAuthentication(HttpServletResponse httpResponse,String username, String password) throws IOException {
            Authentication resultOfAuthentication = tryToAuthenticateWithUsernameAndPassword(username, password);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
            httpResponse.setStatus(HttpServletResponse.SC_OK);
            httpResponse.addHeader("Content-Type", "application/json");
            httpResponse.addHeader("X-Auth-Token", resultOfAuthentication.getDetails().toString());
        }

        private Authentication tryToAuthenticateWithUsernameAndPassword(String username,String password) {
            UsernamePasswordAuthenticationToken requestAuthentication = new UsernamePasswordAuthenticationToken(username, password);
            return tryToAuthenticate(requestAuthentication);
        }

        private void processTokenAuthentication(String token) {
            Authentication resultOfAuthentication = tryToAuthenticateWithToken(token);
            SecurityContextHolder.getContext().setAuthentication(resultOfAuthentication);
        }

        private Authentication tryToAuthenticateWithToken(String token) {
            PreAuthenticatedAuthenticationToken requestAuthentication = new PreAuthenticatedAuthenticationToken(token, null);
            return tryToAuthenticate(requestAuthentication);
        }

        private Authentication tryToAuthenticate(Authentication requestAuthentication) {
            Authentication responseAuthentication = authenticationManager.authenticate(requestAuthentication);
            if (responseAuthentication == null || !responseAuthentication.isAuthenticated()) {
                throw new InternalAuthenticationServiceException("Unable to authenticate Domain User for provided credentials");
            }
            logger.debug("User successfully authenticated");
            return responseAuthentication;
        }

내 컨트롤러는

@RestController
public class UserController {

    @Autowired
    UserService userService;

    /**
     * to pass user info to service
     */
    @RequestMapping(value = "api/v1/signup",method = RequestMethod.POST)
    public String saveUser(@RequestBody User user) {
        userService.saveUser(user);
        return "User registerted successfully";
    }
}

나는 봄에 완전히 새롭습니다, 그것을하는 방법을 도와주세요?

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사용할 때 permitAll모든 인증 된 사용자를 의미하지만 익명 액세스를 비활성화하여 작동하지 않습니다.

원하는 것은 객체와 패턴 configure을 취하는 메소드를 재정의하기 위해 특정 URL을 무시 하는 것입니다.WebSecurityignore

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/api/v1/signup");
}

And remove that line from the HttpSecurity part. This will tell Spring Security to ignore this URL and don't apply any filters to them.

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I have a better way:

http
    .authorizeRequests()
    .antMatchers("/api/v1/signup/**").permitAll()
    .anyRequest().authenticated()

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<http pattern="/resources/**" security="none"/>

Or with Java configuration:

web.ignoring().antMatchers("/resources/**");

Instead of the old:

 <intercept-url pattern="/resources/**" filters="none"/>

for exp . disable security for a login page :

  <intercept-url pattern="/login*" filters="none" />

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This may be not the full answer to your question, however if you are looking for way to disable csrf protection you can do:

@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests()
                .antMatchers("/web/admin/**").hasAnyRole(ADMIN.toString(), GUEST.toString())
                .anyRequest().permitAll()
                .and()
                .formLogin().loginPage("/web/login").permitAll()
                .and()
                .csrf().ignoringAntMatchers("/contact-email")
                .and()
                .logout().logoutUrl("/web/logout").logoutSuccessUrl("/web/").permitAll();
    }

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.inMemoryAuthentication()
                .withUser("admin").password("admin").roles(ADMIN.toString())
                .and()
                .withUser("guest").password("guest").roles(GUEST.toString());
    }

}

I have included full configuration but the key line is:

.csrf().ignoringAntMatchers("/contact-email")

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As @M.Deinum already wrote the answer.

I tried with api /api/v1/signup. it will bypass the filter/custom filter but an additional request invoked by the browser for /favicon.ico, so, I add this also in web.ignoring() and it works for me.

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/api/v1/signup", "/favicon.ico");
}

Maybe this is not required for the above question.

참고URL : https://stackoverflow.com/questions/30366405/how-to-disable-spring-security-for-particular-url